2x^2+100=-30x

Solution for 2x^2+100=-30x equation:

2x^2+100=-30x

We move all terms to the left:

2x^2+100-(-30x)=0

We get rid of parentheses

2x^2+30x+100=0

a = 2; b = 30; c = +100;
Δ = b2-4ac
Δ = 302-4·2·100
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*2}=\frac{-40}{4}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*2}=\frac{-20}{4}
=-5
$